You are given an array a, of n elements. Find the minimum index based distance between two distinct elements of the array, x and y. Return -1, if either x or y does not exist in the array.
Question
You are given an array a, of n elements. Find the minimum index based distance between two distinct elements of the array, x and y. Return -1, if either x or y does not exist in the array.
Solution
Sure, here is a Python solution for the problem:
def min_distance(arr, x, y):
# Initialize minimum distance
min_dist = float('inf')
# Check if x and y are in arr
if x not in arr or y not in arr:
return -1
# Traverse through the array
for i in range(len(arr)):
for j in range(i+1, len(arr)):
# If x and y are found, update min_dist
if ((arr[i] == x and arr[j] == y) or (arr[j] == x and arr[i] == y)) and min_dist > abs(i-j):
min_dist = abs(i-j)
return min_dist
This function min_distance takes an array arr and two elements x and y as input. It first checks if x and y are in arr. If either x or y does not exist in arr, it returns -1. Then it traverses through the array. For each element, it checks the rest of the array for x and y. If x and y are found, it updates min_dist with the absolute difference of their indices if this difference is smaller than the current min_dist. Finally, it returns min_dist which is the minimum index based distance between x and y.
Please note that this solution has a time complexity of O(n^2) due to the nested loop. If the array is large, this solution might be slow.
Similar Questions
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