You are given a 0-indexed integer array nums having length n, an integer indexDifference, and an integer valueDifference.Your task is to find two indices i and j, both in the range [0, n - 1], that satisfy the following conditions:abs(i - j) >= indexDifference, andabs(nums[i] - nums[j]) >= valueDifferenceReturn an integer array answer, where answer = [i, j] if there are two such indices, and answer = [-1, -1] otherwise. If there are multiple choices for the two indices, return any of them.Note: i and j may be equal. Example 1:Input: nums = [5,1,4,1], indexDifference = 2, valueDifference = 4Output: [0,3]Explanation: In this example, i = 0 and j = 3 can be selected.abs(0 - 3) >= 2 and abs(nums[0] - nums[3]) >= 4.Hence, a valid answer is [0,3].[3,0] is also a valid answer.Example 2:Input: nums = [2,1], indexDifference = 0, valueDifference = 0Output: [0,0]Explanation: In this example, i = 0 and j = 0 can be selected.abs(0 - 0) >= 0 and abs(nums[0] - nums[0]) >= 0.Hence, a valid answer is [0,0].Other valid answers are [0,1], [1,0], and [1,1].Example 3:Input: nums = [1,2,3], indexDifference = 2, valueDifference = 4Output: [-1,-1]Explanation: In this example, it can be shown that it is impossible to find two indices that satisfy both conditions.Hence, [-1,-1] is returned. Constraints:1 <= n == nums.length <= 1050 <= nums[i] <= 1090 <= indexDifference <= 1050 <= valueDifference <= 109
Question
You are given a 0-indexed integer array nums having length n, an integer indexDifference, and an integer valueDifference.Your task is to find two indices i and j, both in the range [0, n - 1], that satisfy the following conditions:abs(i - j) >= indexDifference, andabs(nums[i] - nums[j]) >= valueDifferenceReturn an integer array answer, where answer = [i, j] if there are two such indices, and answer = [-1, -1] otherwise. If there are multiple choices for the two indices, return any of them.Note: i and j may be equal. Example 1:Input: nums = [5,1,4,1], indexDifference = 2, valueDifference = 4Output: [0,3]Explanation: In this example, i = 0 and j = 3 can be selected.abs(0 - 3) >= 2 and abs(nums[0] - nums[3]) >= 4.Hence, a valid answer is [0,3].[3,0] is also a valid answer.Example 2:Input: nums = [2,1], indexDifference = 0, valueDifference = 0Output: [0,0]Explanation: In this example, i = 0 and j = 0 can be selected.abs(0 - 0) >= 0 and abs(nums[0] - nums[0]) >= 0.Hence, a valid answer is [0,0].Other valid answers are [0,1], [1,0], and [1,1].Example 3:Input: nums = [1,2,3], indexDifference = 2, valueDifference = 4Output: [-1,-1]Explanation: In this example, it can be shown that it is impossible to find two indices that satisfy both conditions.Hence, [-1,-1] is returned. Constraints:1 <= n == nums.length <= 1050 <= nums[i] <= 1090 <= indexDifference <= 1050 <= valueDifference <= 109
Solution
The problem is asking to find two indices in the given array that satisfy two conditions. The absolute difference between the indices should be greater than or equal to the given indexDifference, and the absolute difference between the values at these indices should be greater than or equal to the given valueDifference. If such indices exist, return them, otherwise return [-1, -1].
Here is a step-by-step solution:
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Initialize two variables, i and j, to 0. These will be used to iterate over the array.
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Start a while loop that continues until i and j reach the end of the array.
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Inside the loop, check if the absolute difference between i and j is greater than or equal to indexDifference and the absolute difference between nums[i] and nums[j] is greater than or equal to valueDifference. If both conditions are satisfied, return [i, j].
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If the conditions are not satisfied, increment j if it is less than the length of the array minus 1. If j has reached the end of the array, increment i and reset j to i.
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If the loop completes without finding suitable indices, return [-1, -1].
This algorithm will find two indices that satisfy the conditions if they exist. If there are multiple valid pairs of indices, it will return the first one it finds.
Similar Questions
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Problem Statement You are given a function, static int ElementsAndIndices(int[] arr){} The function takes an integer array 'arr' of size 'n' as its arguments. Implement the function to find and return the number of array elements which are equal to their index value in array i.e. arr[k] = k, 0 <= k < n. Note: Indexing starts from 0. Return -1 if 'arr' is empty or None in case of python Example: Input: 10 1 12 3 5 8 9 7 12 23 Output: 3 Explanation: Index Element 0 10 1 1 2 12 3 3 4 5 5 8 6 9 7 7 8 12 9 23 Elements at index {1, 3, 7} are equal to their index values {1, 3, 7} respectively. Since, these are 3 elements, thus, output is 3. The custom input format for the above case: 10 10 1 12 3 5 8 9 7 12 23 (The first line represents the size of the array, the second line represents the elements of the array) Sample input -3 0 1 3 5 7 Sample Output 1 The custom input format for the above case: 6 -3 0 1 3 5 7 (The first line represents the size of the array, the second line represents the elements of the array) Instructions : This is a template based question, DO NOT write the "main" function. Your code is judged by an automated system, do not write any additional welcome/greeting messages. "Save and Test" only checks for basic test cases, more rigorous cases will be used to judge your code while scoring. Additional score will be given for writing optimized code both in terms of memory and execution time. Now let's start coding : Language: Java 17.0 Day Mode Read-only code below . . . 1 class SolutionClass { 2 public static void main(String[] args) throws java.lang.Exception { 3 //Input read from STDIN 4 int result = ElementsAndIndices(arr); 5 //Value in result printed to STDOUT 6 } 7 } 8 Write your code below . . . 9 static int ElementsAndIndices(int[] arr) throws java.lang.Exception 10 { 11 /* Write your code here. */ 12 } 13 14 15
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