Problem Statement You are given a function, static int ElementsAndIndices(int[] arr){} The function takes an integer array 'arr' of size 'n' as its arguments. Implement the function to find and return the number of array elements which are equal to their index value in array i.e. arr[k] = k, 0 <= k < n. Note: Indexing starts from 0. Return -1 if 'arr' is empty or None in case of python Example: Input: 10 1 12 3 5 8 9 7 12 23 Output: 3 Explanation: Index Element 0 10 1 1 2 12 3 3 4 5 5 8 6 9 7 7 8 12 9 23 Elements at index {1, 3, 7} are equal to their index values {1, 3, 7} respectively. Since, these are 3 elements, thus, output is 3. The custom input format for the above case: 10 10 1 12 3 5 8 9 7 12 23 (The first line represents the size of the array, the second line represents the elements of the array) Sample input -3 0 1 3 5 7 Sample Output 1 The custom input format for the above case: 6 -3 0 1 3 5 7 (The first line represents the size of the array, the second line represents the elements of the array) Instructions : This is a template based question, DO NOT write the "main" function. Your code is judged by an automated system, do not write any additional welcome/greeting messages. "Save and Test" only checks for basic test cases, more rigorous cases will be used to judge your code while scoring. Additional score will be given for writing optimized code both in terms of memory and execution time. Now let's start coding : Language: Java 17.0 Day Mode Read-only code below . . . 1 class SolutionClass { 2 public static void main(String[] args) throws java.lang.Exception { 3 //Input read from STDIN 4 int result = ElementsAndIndices(arr); 5 //Value in result printed to STDOUT 6 } 7 } 8 Write your code below . . . 9 static int ElementsAndIndices(int[] arr) throws java.lang.Exception 10 { 11 /* Write your code here. */ 12 } 13 14 15
Question
Problem Statement You are given a function, static int ElementsAndIndices(int[] arr){}
The function takes an integer array 'arr' of size 'n' as its arguments. Implement the function to find and return the number of array elements which are equal to their index value in array i.e. arr[k] = k, 0 <= k < n. Note: Indexing starts from 0. Return -1 if 'arr' is empty or None in case of python
Example: Input: 10 1 12 3 5 8 9 7 12 23 Output: 3 Explanation: Index Element 0 10 1 1 2 12 3 3 4 5 5 8 6 9 7 7 8 12 9 23 Elements at index {1, 3, 7} are equal to their index values {1, 3, 7} respectively. Since, these are 3 elements, thus, output is 3.
The custom input format for the above case: 10 10 1 12 3 5 8 9 7 12 23 (The first line represents the size of the array, the second line represents the elements of the array) Sample input -3 0 1 3 5 7 Sample Output 1 The custom input format for the above case: 6 -3 0 1 3 5 7 (The first line represents the size of the array, the second line represents the elements of the array) Instructions : This is a template based question, DO NOT write the "main" function. Your code is judged by an automated system, do not write any additional welcome/greeting messages. "Save and Test" only checks for basic test cases, more rigorous cases will be used to judge your code while scoring. Additional score will be given for writing optimized code both in terms of memory and execution time. Now let's start coding : Language: Java 17.0
Day Mode Read-only code below . . . 1 class SolutionClass { 2 public static void main(String[] args) throws java.lang.Exception { 3 //Input read from STDIN 4 int result = ElementsAndIndices(arr); 5 //Value in result printed to STDOUT 6 } 7 } 8 Write your code below . . . 9 static int ElementsAndIndices(int[] arr) throws java.lang.Exception 10 { 11 /* Write your code here. */ 12 } 13 14 15
Solution
Here is the Java code to solve the problem:
static int ElementsAndIndices(int[] arr) throws java.lang.Exception
{
// Check if the array is empty
if (arr == null || arr.length == 0) {
return -1;
}
int count = 0;
// Iterate over the array
for (int i = 0; i < arr.length; i++) {
// Check if the element is equal to its index
if (arr[i] == i) {
count++;
}
}
return count;
}
This function works by iterating over each element in the array and checking if it is equal to its index. If it is, it increments a counter. At the end of the function, it returns the counter, which represents the number of elements that are equal to their index. If the array is empty or null, it returns -1.
Similar Questions
Find which element and Indices are equal 3.5 marks Problem Statement You are given a function, int ElementsAndIndices(int arr[], int n); The function takes an integer array 'arr' of size 'n' as its arguments. Implement the function to find and return the number of array elements which are equal to their index value in array i.e. arr[k] = k, 0 <= k < n. Note: Indexing starts from 0. Return -1 if 'arr' is empty or None in case of python Example: Input: 10 1 12 3 5 8 9 7 12 23 Output: 3 Explanation: Index Element 0 10 1 1 2 12 3 3 4 5 5 8 6 9 7 7 8 12 9 23 Elements at index {1, 3, 7} are equal to their index values {1, 3, 7} respectively. Since, these are 3 elements, thus, output is 3. The custom input format for the above case: 10 10 1 12 3 5 8 9 7 12 23 (The first line represents the size of the array, the second line represents the elements of the array) Sample input -3 0 1 3 5 7 Sample Output 1 The custom input format for the above case: 6 -3 0 1 3 5 7 (The first line represents the size of the array, the second line represents the elements of the array) Instructions : This is a template based question, DO NOT write the "main" function. Your code is judged by an automated system, do not write any additional welcome/greeting messages. "Save and Test" only checks for basic test cases, more rigorous cases will be used to judge your code while scoring. Additional score will be given for writing optimized code both in terms of memory and execution time.
Given an array Arr of N positive integers. Your task is to find the elements whose value is equal to that of its index value ( Consider 1-based indexing ).
public class Main { public static int ElementsAndIndices(int[] arr) { if (arr == null || arr.length == 0) { return -1; } int count = 0; for (int i = 0; i < arr.length; i++) { if (arr[i] == i) { count++; } } return count; } public static void main(String[] args) { int[] arr = {10, 1, 12, 3, 5, 8, 9, 7, 12, 23}; System.out.println(ElementsAndIndices(arr)); // Output: 3 int[] arr2 = {-3, 0, 1, 3, 5, 7}; System.out.println(ElementsAndIndices(arr2)); // Output: 1 } } :6: error: cannot find symbol int result = ElementsAndIndices(arr); ^ symbol: method ElementsAndIndices(int[]) location: class SolutionClass 1 error it is showing this error
Given an unsorted array Arr[] of N integers and a Key which is present in this array. You need to write a program to find the start index( index where the element is first found from left in the array ) and end index( index where the element is first found from right in the array ).If the key does not exist in the array then return -1 for both start and end index in this case.
You are given an integer array and a positive integer K. You have to tell if there exists i,j,k in the given array such that ar[i]+ar[j]+ar[k]=K, i≠j≠k.Input FormatThe first line of input contains T - the number of test cases. Its followed by 2T lines, the first line contains N and K - the size of the array and the number K. The second line contains the elements of the array.Output FormatFor each test case, print "true" if the arrays contains such elements, false otherwise, separated by new line.Constraints30 points1 <= T <= 1003 <= N <= 10070 points1 <= T <= 1003 <= N <= 1000General Constraints-100000 <= A[i] <= 1000000 <= K <= 100000ExampleInput35 601 20 40 100 8012 5412 45 52 65 21 645 234 -100 14 575 -80 1123 155 5 5Outputfalsetruetrue
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