Given an array of integers, your task is to find the smallest and second smallest element in the array. If smallest and second smallest do not exist, print -1.
Question
Given an array of integers, your task is to find the smallest and second smallest element in the array. If smallest and second smallest do not exist, print -1.
Solution
To find the smallest and second smallest elements in an array of integers, follow these steps:
-
Initialize two variables,
smallestandsecond_smallest, with values that are greater than any possible element in the array. For example, you can setsmallestto infinity andsecond_smallestto infinity + 1. -
Iterate through each element in the array.
-
Compare the current element with the value of
smallest. If the current element is smaller thansmallest, updatesmallestwith the value of the current element. -
If the current element is not smaller than
smallestbut smaller thansecond_smallest, updatesecond_smallestwith the value of the current element. -
After iterating through all the elements, check if
second_smallestis still greater thansmallest. If it is, it means that there is no second smallest element in the array. In this case, print -1. -
Otherwise, print the values of
smallestandsecond_smallest.
Here is an example implementation in Python:
def find_smallest_and_second_smallest(arr):
smallest = float('inf')
second_smallest = float('inf') + 1
for num in arr:
if num < smallest:
second_smallest = smallest
smallest = num
elif num < second_smallest and num != smallest:
second_smallest = num
if second_smallest == float('inf') + 1:
print(-1)
else:
print(smallest, second_smallest)
You can call this function with your array as an argument to find the smallest and second smallest elements.
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