Let's heat 100.0 mL of water using a flame.Remember, the density of water around 20°C is 1.00 g.mL-1 and the specific heat capacity of water is 4.184 J.g-1.K-1.We use a thermometer to measure the initial and final temperatures:Initial readingFinal readingUse the equation q = mCΔT to work out how much energy the water has absorbed in Joules. Report your answer to one decimal place (include units in your answer):
Question
Let's heat 100.0 mL of water using a flame.Remember, the density of water around 20°C is 1.00 g.mL-1 and the specific heat capacity of water is 4.184 J.g-1.K-1.We use a thermometer to measure the initial and final temperatures:Initial readingFinal readingUse the equation q = mCΔT to work out how much energy the water has absorbed in Joules. Report your answer to one decimal place (include units in your answer):
Solution 1
To calculate the energy absorbed by the water, we need to know the initial and final temperatures, which are not provided in your question. However, I can explain how to use the formula q = mCΔT.
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First, calculate the mass of the water. Since the density of water is 1.00 g/mL, and you have 100.0 mL of water, the mass (m) of the water is 100.0 g.
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Next, find the change in temperature (ΔT). This is the final temperature minus the initial temperature. Without these values, we can't calculate ΔT.
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Now, you can calculate the energy absorbed (q) by the water. Multiply the mass of the water (m) by the specific heat capacity of water (C), and then multiply that by the change in temperature (ΔT).
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The result will be the energy absorbed by the water in Joules.
Remember to report your answer to one decimal place.
Solution 2
To calculate the energy absorbed by the water, we need to know the initial and final temperatures, which are not provided in your question. However, I can explain the steps you would take once you have these values.
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Calculate the change in temperature (ΔT) by subtracting the initial temperature from the final temperature.
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Convert the volume of water to mass. Since the density of water is 1.00 g/mL, and you have 100.0 mL of water, the mass (m) of the water is 100.0 g.
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Use the formula q = mCΔT to calculate the energy absorbed. In this formula, q is the energy absorbed, m is the mass of the water, C is the specific heat capacity of the water, and ΔT is the change in temperature.
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Plug in the values you have into the formula and calculate q.
Remember to report your answer in Joules to one decimal place.
Similar Questions
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