What is the heat needed to heat 150 g of water from 10.0 °C to 100 °C? (specific heat of water = 4,186 J/kg °C)
Question
What is the heat needed to heat 150 g of water from 10.0 °C to 100 °C? (specific heat of water = 4,186 J/kg °C)
Solution
To calculate the heat needed to heat the water, we can use the formula for heat transfer:
Q = mcΔT
where:
- Q is the heat energy (in Joules),
- m is the mass of the substance (in kg),
- c is the specific heat capacity (in J/kg°C), and
- ΔT is the change in temperature (in °C).
Given:
- m = 150 g = 0.15 kg (since 1 kg = 1000 g),
- c = 4,186 J/kg°C, and
- ΔT = 100°C - 10°C = 90°C.
Substituting these values into the formula, we get:
Q = 0.15 kg * 4,186 J/kg°C * 90°C = 56,493 J.
So, the heat needed to heat 150 g of water from 10.0 °C to 100 °C is 56,493 Joules.
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