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x−2y+3z=9(1)−x+3y−z=−6(2)2x−5y+5z=17

Question

x−2y+3z=9(1)−x+3y−z=−6(2)2x−5y+5z=17

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Solution

The system of equations you provided is:

x - 2y + 3z = 9 (Equation 1) -x + 3y - z = -6 (Equation 2) 2x - 5y + 5z = 17 (Equation 3)

Let's solve this system step by step:

Step 1: Add Equation 1 and Equation 2. This will eliminate x.

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