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5(2z−1)=−(3z−21)

Question

5(2z−1)=−(3z−21)

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Solution

Sure, let's solve the equation step by step.

  1. Distribute the 5 on the left side of the equation: 10z - 5 = -(3z - 21)
  2. Distribute the -1 on the right side of the equation: 10z - 5 = -3z + 21
  3. Move -3z from the right side to the left side by adding 3z to both sides: 10z + 3z - 5 = 21
  4. Simplify the left side: 13z - 5 = 21
  5. Move -5 from the left side to the right side by adding 5 to both sides: 13z = 21 + 5
  6. Simplify the right side: 13z = 26
  7. Divide both sides by 13 to solve for z: z = 26 / 13
  8. Simplify to find the solution: z = 2

This problem has been solved

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