A ball of mass 0.2 kg is thrown upwards with a speed of 2 m/s. Calculate the maximum height reached by the ball.
Question
A ball of mass 0.2 kg is thrown upwards with a speed of 2 m/s. Calculate the maximum height reached by the ball.
Solution
Sure, to solve this problem, we will use the principle of conservation of energy. The initial kinetic energy of the ball will be converted into potential energy at the maximum height.
Step 1: Calculate the initial kinetic energy of the ball using the formula:
Kinetic Energy = 0.5 * mass * (speed)^2
Substituting the given values:
Kinetic Energy = 0.5 * 0.2 kg * (2 m/s)^2 = 0.4 Joules
Step 2: At the maximum height, the ball's velocity will be zero, so it will have no kinetic energy. All the initial kinetic energy will be converted into gravitational potential energy. We can calculate the height using the formula for potential energy:
Potential Energy = mass * gravity * height
We know that the potential energy at the maximum height will be equal to the initial kinetic energy. So we can set them equal to each other and solve for height:
0.4 Joules = 0.2 kg * 9.8 m/s^2 * height
Solving for height gives:
Height = 0.4 Joules / (0.2 kg * 9.8 m/s^2) = 2.04 meters
So, the maximum height reached by the ball is approximately 2.04 meters.
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