A ball with a mass of 0.2 kg is thrown vertically upward with an initial velocity of 10 m/s. What is its kinetic energy when it reaches its maximum height?*2 pointsa) 0 Jb) 10 Jc) 20 Jd) 40 J
Question
A ball with a mass of 0.2 kg is thrown vertically upward with an initial velocity of 10 m/s. What is its kinetic energy when it reaches its maximum height?*2 pointsa) 0 Jb) 10 Jc) 20 Jd) 40 J
Solution
The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass and v is the velocity.
When the ball reaches its maximum height, its velocity is 0 (because it stops for a moment before falling back down).
So, if we substitute m = 0.2 kg and v = 0 m/s into the formula, we get KE = 1/2 * 0.2 kg * (0 m/s)^2 = 0 J.
Therefore, the answer is a) 0 J.
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