A ball is thrown vertically upwards with a velocity of 49 m/s and g =9.8 m/s2Calculate the max height it rises up to?112.5 mwrong245 m122.5 mcorrectnone of these12. Calculate the total time it takes to reach back to surface?20 sec
Question
A ball is thrown vertically upwards with a velocity of 49 m/s and g =9.8 m/s2Calculate the max height it rises up to?112.5 mwrong245 m122.5 mcorrectnone of these12. Calculate the total time it takes to reach back to surface?20 sec
Solution
The maximum height a ball reaches when thrown vertically upwards can be calculated using the formula:
h = (v^2) / (2g)
where: v = initial velocity = 49 m/s g = acceleration due to gravity = 9.8 m/s^2
Substituting the given values into the formula, we get:
h = (49^2) / (2*9.8) = 122.5 m
So, the ball rises up to a maximum height of 122.5 m.
The total time it takes for the ball to reach back to the surface can be calculated using the formula:
t = 2v / g
Substituting the given values into the formula, we get:
t = 2*49 / 9.8 = 10 s
However, this is the time it takes for the ball to reach its maximum height. Since the ball takes the same amount of time to fall back down, the total time is 2*10 = 20 s.
So, the ball takes a total of 20 seconds to reach back to the surface.
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