Findthey -interceptoftheparabolay = x2 − 6x + 4.
Question
Findthey -interceptoftheparabolay = x2 − 6x + 4.
Solution
The y-intercept of a parabola (or any function) is the point where the graph of the function intersects the y-axis. This always occurs when x = 0.
So, to find the y-intercept of the parabola y = x^2 - 6x + 4, we substitute x = 0 into the equation:
y = (0)^2 - 6*(0) + 4 y = 0 - 0 + 4 y = 4
So, the y-intercept of the parabola is 4.
Similar Questions
Findthey -interceptoftheparabolay = x2 − 65.
Find the equation of the axis of symmetry of the following parabola algebraically.y, equals, x, squared, minus, 6y=x 2 −6
Graph parabola by completing the square. Label the vertex, the axis of symmetry, and two other points for the equation y = x2 + 6x + 4.
Findthevertexoftheparabolay = x2 + 4x + 6.Simplify both coordinates and write them as proper fractions, improper fractions, or integers.
Findthevertexoftheparabolay = x2 + 3x.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.