Findthevertexoftheparabolay = x2 + 4x + 6.Simplify both coordinates and write them as proper fractions, improper fractions, or integers.

To find the vertex of the parabola given by the equation y = x^2 + 4x + 6, we can use the formula for the x-coordinate of the vertex of a parabola, which is -b/2a, where a and b are the coefficients of x^2 and x, respectively, in the equation of the parabola.

In this case, a = 1 (the coefficient of x^2) and b = 4 (the coefficient of x), so the x-coordinate of the vertex is -b/2a = -4/(2*1) = -2.

To find the y-coordinate of the vertex, we substitute the x-coordinate of the vertex into the equation of the parabola. So, y = (-2)^2 + 4*(-2) + 6 = 4 - 8 + 6 = 2.

Therefore, the vertex of the parabola y = x^2 + 4x + 6 is (-2, 2).