The axis of symmetry for a parabola given by the equation y = ax^2 + bx + c is given by the formula x = -b/2a.

In the equation y = x^2 - 354, the coefficient a is 1 (since x^2 is the same as 1*x^2) and the coefficient b is 0 (since there is no term with x).

So, the axis of symmetry is x = -0/(2*1) = 0.

Therefore, the equation of the axis of symmetry for the parabola y = x^2 - 354 is x = 0.

Question

The axis of symmetry for a parabola given by the equation y = ax^2 + bx + c is given by the formula x = -b/2a.

In the equation y = x^2 - 354, the coefficient a is 1 (since x^2 is the same as 1*x^2) and the coefficient b is 0 (since there is no term with x).

So, the axis of symmetry is x = -0/(2*1) = 0.

Therefore, the equation of the axis of symmetry for the parabola y = x^2 - 354 is x = 0.

Knowee AI · Accepted Answer

The axis of symmetry for a parabola given by the equation y = ax^2 + bx + c is given by the formula x = -b/2a.

In the equation y = x^2 - 354, the coefficient a is 1 (since x^2 is the same as 1*x^2) and the coefficient b is 0 (since there is no term with x).

So, the axis of symmetry is x = -0/(2*1) = 0.

Therefore, the equation of the axis of symmetry for the parabola y = x^2 - 354 is x = 0.

Findtheequationoftheaxisofsymmetryfortheparabolay = x2 − 354.Simplify any numbers and write them as proper fractions, improper fractions, or integers.