Determine the number of moles of sodium hydroxide which react with the dilute sulfuric acid.molCalculate the concentration of the aqueous sodium hydroxide in mol/dm³.mol/dmCalculate the concentration of the aqueous sodium hydroxide in g/dm³.g/dm³[5]any organic compounds contain carbon, hydrogen and oxygen only. An organic compound V has the following composition by mass.C, 48.65%; H, 8.11%; O, 43.24%Calculate the empirical formula of compound V.empirical formula =
Question
Determine the number of moles of sodium hydroxide which react with the dilute sulfuric acid.molCalculate the concentration of the aqueous sodium hydroxide in mol/dm³.mol/dmCalculate the concentration of the aqueous sodium hydroxide in g/dm³.g/dm³[5]any organic compounds contain carbon, hydrogen and oxygen only. An organic compound V has the following composition by mass.C, 48.65%; H, 8.11%; O, 43.24%Calculate the empirical formula of compound V.empirical formula =
Solution
I'm sorry, but you didn't provide enough information for me to answer the first three questions. I need to know the volume of the sodium hydroxide solution and the concentration of the sulfuric acid.
However, I can help you with the last question.
To find the empirical formula of compound V, we need to convert the percentages to grams.
So, we have:
- 48.65 g of Carbon (C)
- 8.11 g of Hydrogen (H)
- 43.24 g of Oxygen (O)
Next, we convert the mass of each element to moles.
- For Carbon: 48.65 g / 12.01 g/mol = 4.05 mol
- For Hydrogen: 8.11 g / 1.01 g/mol = 8.02 mol
- For Oxygen: 43.24 g / 16.00 g/mol = 2.70 mol
Then, we divide each number of moles by the smallest number of moles to get the ratio of the atoms.
- For Carbon: 4.05 mol / 2.70 mol = 1.5
- For Hydrogen: 8.02 mol / 2.70 mol = 3
- For Oxygen: 2.70 mol / 2.70 mol = 1
Since empirical formulas should be in whole numbers, we multiply each number by 2 to get rid of the decimal.
So, the empirical formula of compound V is C3H6O2.
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