What is the equation for calculating moles?Mass × MrMass/MrMr/massMass – Mr 2How many moles are there in 1.2 g of sodium hydroxide?1.20.034403What is the first thing you should do when calculating reacting masses?Calculate the moles for each substanceCalculate the Mr for each substanceWrite out the balanced equationCalculate the ratio of the moles for each substance4What do we call a reactant that is left over at the end of a reaction?BalancedWastedLimitingIn excess5Three moles of Mg react with 5 moles of HCl to form MgCl2 and H2. What is the limiting reagent in this reaction?HClMgMgCl2H2
Question
What is the equation for calculating moles?Mass × MrMass/MrMr/massMass – Mr 2How many moles are there in 1.2 g of sodium hydroxide?1.20.034403What is the first thing you should do when calculating reacting masses?Calculate the moles for each substanceCalculate the Mr for each substanceWrite out the balanced equationCalculate the ratio of the moles for each substance4What do we call a reactant that is left over at the end of a reaction?BalancedWastedLimitingIn excess5Three moles of Mg react with 5 moles of HCl to form MgCl2 and H2. What is the limiting reagent in this reaction?HClMgMgCl2H2
Solution
The text you provided seems to be a series of questions and multiple choice answers, but they are not clearly separated. Here are the answers to the questions I could identify:
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The equation for calculating moles is Mass/Mr (molar mass).
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To calculate the number of moles in 1.2 g of sodium hydroxide, you would use the equation from the first question. The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. So, the calculation would be 1.2 g / 40 g/mol = 0.03 moles.
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The first thing you should do when calculating reacting masses is to write out the balanced equation.
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A reactant that is left over at the end of a reaction is called "in excess".
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In the reaction of Mg and HCl to form MgCl2 and H2, the limiting reagent would be determined by comparing the stoichiometric ratio of the reactants to the actual ratio. Without the balanced equation, it's not possible to definitively identify the limiting reagent.
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