The given chemical equation shows a reaction of chlorine with cold, dilute solution of sodiumhydroxide.(l)2(aq)(aq)(aq)2(g) OHNaClONaCl2NaOHCl How many grams of sodium hydroxide will be used to synthesise 6 moles ofsodium chlorate(I)?(Note: Molar mass of Na = 23 g mol–1, Cl = 35.5 g mol–1, H = 1 g mol–1 and O = 16 g mol–1)A. 13.33 gB. 80 gC. 240 gD. 480 g
Question
The given chemical equation shows a reaction of chlorine with cold, dilute solution of sodiumhydroxide.(l)2(aq)(aq)(aq)2(g) OHNaClONaCl2NaOHCl How many grams of sodium hydroxide will be used to synthesise 6 moles ofsodium chlorate(I)?(Note: Molar mass of Na = 23 g mol–1, Cl = 35.5 g mol–1, H = 1 g mol–1 and O = 16 g mol–1)A. 13.33 gB. 80 gC. 240 gD. 480 g
Solution
The balanced chemical equation is:
3Cl2(g) + 6NaOH(aq) → 5NaCl(aq) + NaClO3(aq) + 3H2O(l)
From the balanced equation, we can see that 6 moles of sodium hydroxide (NaOH) are needed to produce 1 mole of sodium chlorate (NaClO3). Therefore, to produce 6 moles of sodium chlorate, we will need 6*6 = 36 moles of sodium hydroxide.
The molar mass of sodium hydroxide (NaOH) is calculated as follows:
Na = 23 g/mol O = 16 g/mol H = 1 g/mol
So, molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Therefore, the mass of sodium hydroxide needed is:
Mass = Moles * Molar mass Mass = 36 moles * 40 g/mol = 1440 g
So, none of the options (A. 13.33 g, B. 80 g, C. 240 g, D. 480 g) are correct. The correct answer should be 1440 g.
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