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A line passes through the point (-1, 2) and is parallel to the line 2x + y=6.What is the equation of the line?Ay = -2x + 4By = -2xCy = 2x +2Dy = 2x - 4

Question

A line passes through the point (-1, 2) and is parallel to the line 2x + y=6.What is the equation of the line?Ay = -2x + 4By = -2xCy = 2x +2Dy = 2x - 4

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Solution

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Step 1: Find the slope of the given line The given line is 2x + y = 6. We can rewrite this in slope-intercept form to find the slope. Subtract 2x from both sides to get y = -2x + 6. So, the slope of the given line is -2.

Step 2: Use the slope of the parallel line Lines that are parallel have the same slope. So, the slope of the line we're trying to find is also -2.

Step 3: Use the point to find the y-intercept We know that the line we're looking for passes through the point (-1, 2). We can substitute these values into the equation y = mx + b to find the y-intercept.

2 = -2*(-1) + b 2 = 2 + b Subtract 2 from both sides to get b = 0.

Step 4: Write the equation of the line Now we know the slope and the y-intercept, we can write the equation of the line. It is y = -2x + 0, or simply y = -2x.

So, the correct answer is B: y = -2x.

This problem has been solved

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