Which line is parallel to the line that passes through the points (-2,-2) and (2, 6)?

To find a line parallel to the one that passes through the points (-2,-2) and (2, 6), we first need to find the slope of the given line.

The formula for the slope (m) between two points (x1, y1) and (x2, y2) is:

m = (y2 - y1) / (x2 - x1)

Substituting the given points into the formula, we get:

m = (6 - (-2)) / (2 - (-2)) = 8 / 4 = 2

So, the slope of the line that passes through the points (-2,-2) and (2, 6) is 2.

Parallel lines have the same slope. Therefore, any line with a slope of 2 is parallel to the line that passes through the points (-2,-2) and (2, 6).

The general equation for a line is y = mx + b, where m is the slope and b is the y-intercept.

Since we know the slope (m) is 2, the equation for any line parallel to the given line will be y = 2x + b.

The value of b can be any real number. For example, if b = 0, the equation of the line is y = 2x. If b = 1, the equation of the line is y = 2x + 1, and so on. All these lines are parallel to the line that passes through the points (-2,-2) and (2, 6).