Find the equation of the line that passes through the following two points:(2, -2) and (-2, 6)
Question
Find the equation of the line that passes through the following two points:(2, -2) and (-2, 6)
Solution
Step 1: Find the slope (m) of the line. The formula to find the slope between two points (x1, y1) and (x2, y2) is (y2 - y1) / (x2 - x1).
Using the given points (2, -2) and (-2, 6), the slope m = (6 - (-2)) / (-2 - 2) = 8 / -4 = -2.
Step 2: Use the point-slope form of a line, which is y - y1 = m(x - x1). You can use either of the given points for (x1, y1). Let's use (2, -2).
Substituting the values, we get y - (-2) = -2(x - 2).
Step 3: Simplify the equation to get it in the slope-intercept form (y = mx + b).
y + 2 = -2x + 4.
Subtract 2 from both sides to get the final equation: y = -2x + 2.
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