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Find an equation for the line that passes through the points −3, 4 and −1, 6.

Question

Find an equation for the line that passes through the points −3, 4 and −1, 6.

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Solution

To find the equation of the line that passes through the points (-3, 4) and (-1, 6), we first need to find the slope (m) of the line. The formula for the slope is:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points. Substituting the given points into the formula, we get:

m = (6 - 4) / (-1 - (-3)) = 2 / 2 = 1

So, the slope of the line is 1.

Next, we use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

Substituting the slope and one of the points into the equation, we get:

y - 4 = 1(x - (-3))

Simplifying this equation, we get:

y - 4 = x + 3

Finally, we rearrange the equation to the slope-intercept form (y = mx + b), we get:

y = x + 7

So, the equation of the line that passes through the points (-3, 4) and (-1, 6) is y = x + 7.

This problem has been solved

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