In a given period of time, 0.0250moles of NH3 effuses. How many moles of CO2 would effuse in to the same period of time?

To answer this question, we need to use Graham's law of effusion. This law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

The formula for Graham's law of effusion is: (Rate of effusion of gas 1) / (Rate of effusion of gas 2) = sqrt(Molar mass of gas 2 / Molar mass of gas 1)

First, we need to find the molar masses of NH3 and CO2. The molar mass of NH3 (Nitrogen (14.01 g/mol) + Hydrogen (1.01 g/mol) * 3) is approximately 17.03 g/mol. The molar mass of CO2 (Carbon (12.01 g/mol) + Oxygen (16.00 g/mol) * 2) is approximately 44.01 g/mol.

Now we can plug these values into the formula:

Rate of NH3 / Rate of CO2 = sqrt(44.01 g/mol / 17.03 g/mol)

Solving for the Rate of CO2 (which is what we're trying to find), we get:

Rate of CO2 = Rate of NH3 / sqrt(44.01 g/mol / 17.03 g/mol)

Given that the rate of NH3 is 0.0250 moles, we can substitute this value into the equation:

Rate of CO2 = 0.0250 moles / sqrt(44.01 g/mol / 17.03 g/mol)

Solving this equation will give us the number of moles of CO2 that would effuse in the same period of time.