In a given period of time, 0.990moles of He effuses. How many moles of CO would effuse in to the same period of time?
Question
In a given period of time, 0.990moles of He effuses. How many moles of CO would effuse in to the same period of time?
Solution
To solve this problem, we can use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
The formula for Graham's law is: (Rate1/Rate2) = sqrt(M2/M1)
Given that the molar mass of He is 4 g/mol and the molar mass of CO is 28 g/mol, we can substitute these values into the formula:
(0.990 moles He / x moles CO) = sqrt(28 g/mol / 4 g/mol)
Solving for x gives us:
x = 0.990 moles He * sqrt(4 g/mol / 28 g/mol)
x = 0.374 moles CO
So, 0.374 moles of CO would effuse in the same period of time.
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