A 98% confidence interval is found to be (32, 42). What is the margin of error?A.10B.9.8C.4.9D.5SUBMITarrow_backPREVIOUS
Question
A 98% confidence interval is found to be (32, 42). What is the margin of error?A.10B.9.8C.4.9D.5SUBMITarrow_backPREVIOUS
Solution
To find the margin of error for the given confidence interval (32, 42), follow these steps:
- Identify the lower limit of the confidence interval: 32.
- Identify the upper limit of the confidence interval: 42.
- Calculate the range of the confidence interval by subtracting the lower limit from the upper limit: 42 - 32 = 10.
- The margin of error is half of the range of the confidence interval: 10 / 2 = 5.
Therefore, the margin of error is:
D. 5
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