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A survey of a random sample of 1,500 young Americans found that 87% had earned their high school diploma. Based on these results, the 95% confidence interval for the proportion of young Americans who have earned their high school diploma is (0.853,0.887) What is the margin of error for this confidence interval? 0.87 0.017 0.95 0.034

Question

A survey of a random sample of 1,500 young Americans found that 87% had earned their high school diploma. Based on these results, the 95% confidence interval for the proportion of young Americans who have earned their high school diploma is (0.853,0.887) What is the margin of error for this confidence interval? 0.87 0.017 0.95 0.034

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Solution

The margin of error for a confidence interval is calculated by subtracting the lower limit of the interval from the upper limit, and then dividing by 2.

In this case, the upper limit of the confidence interval is 0.887 and the lower limit is 0.853.

So, the calculation would be as follows:

(0.887 - 0.853) / 2 = 0.034 / 2 = 0.017

Therefore, the margin of error for this confidence interval is 0.017.

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