To calculate the sample size, we need to use the formula for the margin of error at a given confidence level, which is:

E = Z * (σ/√n)

Where:
E is the margin of error,
Z is the Z-score (which corresponds to the desired confidence level),
σ is the population standard deviation, and
n is the sample size.

We want to solve for n, so we rearrange the formula to:

n = (Z * σ / E)²

Given in the problem, we have:
E = 1 (the desired margin of error),
σ = 4 (the population standard deviation), and
Z = 2.576 (the Z-score that corresponds to a 99% confidence level).

Substituting these values in, we get:

n = (2.576 * 4 / 1)² = 66.0512

Since the sample size must be an integer, we round up to the nearest whole number to ensure that the margin of error is not exceeded. Therefore, the minimum sample size needed is 67.

Question

To calculate the sample size, we need to use the formula for the margin of error at a given confidence level, which is:

E = Z * (σ/√n)

Where:
E is the margin of error,
Z is the Z-score (which corresponds to the desired confidence level),
σ is the population standard deviation, and
n is the sample size.

We want to solve for n, so we rearrange the formula to:

n = (Z * σ / E)²

Given in the problem, we have:
E = 1 (the desired margin of error),
σ = 4 (the population standard deviation), and
Z = 2.576 (the Z-score that corresponds to a 99% confidence level).

Substituting these values in, we get:

n = (2.576 * 4 / 1)² = 66.0512

Since the sample size must be an integer, we round up to the nearest whole number to ensure that the margin of error is not exceeded. Therefore, the minimum sample size needed is 67.

Knowee AI · Accepted Answer

To calculate the sample size, we need to use the formula for the margin of error at a given confidence level, which is:

E = Z * (σ/√n)

Where:
E is the margin of error,
Z is the Z-score (which corresponds to the desired confidence level),
σ is the population standard deviation, and
n is the sample size.

We want to solve for n, so we rearrange the formula to:

n = (Z * σ / E)²

Given in the problem, we have:
E = 1 (the desired margin of error),
σ = 4 (the population standard deviation), and
Z = 2.576 (the Z-score that corresponds to a 99% confidence level).

Substituting these values in, we get:

n = (2.576 * 4 / 1)² = 66.0512

Since the sample size must be an integer, we round up to the nearest whole number to ensure that the margin of error is not exceeded. Therefore, the minimum sample size needed is 67.

A population is known to have a population standard deviation o =4.To ensure that the margin of error is +1 at 99%confidence level,the sample size is at least? Hint:Your answer must be an integer.

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