A boy spotted a bird on top of a VRA low tention wire. He shot an arrow straight up to hit the bird at an initial speed of 15.0 𝘮/𝘴. If the arrow misses the bird, after how much time is it moving downward at a speed of 8.00 𝘮/𝘴? 2 points2.35 𝘴0.714 𝘴1.87 𝘴1.24 𝘴
Question
A boy spotted a bird on top of a VRA low tention wire. He shot an arrow straight up to hit the bird at an initial speed of 15.0 𝘮/𝘴. If the arrow misses the bird, after how much time is it moving downward at a speed of 8.00 𝘮/𝘴? 2 points2.35 𝘴0.714 𝘴1.87 𝘴1.24 𝘴
Solution
To solve this problem, we need to use the equation of motion that relates final velocity, initial velocity, acceleration, and time. The equation is:
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the final velocity (v) is -8.00 m/s (negative because it's moving downward), the initial velocity (u) is 15.0 m/s, and the acceleration (a) is -9.8 m/s² (negative because gravity is pulling the arrow downward).
We can rearrange the equation to solve for time (t):
t = (v - u) / a
Substituting the given values:
t = (-8.00 m/s - 15.0 m/s) / -9.8 m/s²
t = -23.0 m/s / -9.8 m/s²
t = 2.35 s
So, the arrow is moving downward at a speed of 8.00 m/s after 2.35 seconds.
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