A dart is thrown horizontally with an initial speed of 18 m/s toward point P, the bull's eye of the dart board. The dart hits at point Q on the rim, vertically below P, 0.20 seconds later. What is the distance PQ?Neglect air friction and express your answer in meters.
Question
A dart is thrown horizontally with an initial speed of 18 m/s toward point P, the bull's eye of the dart board. The dart hits at point Q on the rim, vertically below P, 0.20 seconds later. What is the distance PQ?Neglect air friction and express your answer in meters.
Solution
To solve this problem, we need to use the formula for horizontal motion, which is:
distance = speed * time
We know that the speed of the dart is 18 m/s and the time it takes to hit the point Q is 0.20 seconds. So, we can substitute these values into the formula:
distance PQ = 18 m/s * 0.20 s = 3.6 meters
So, the distance between point P and Q is 3.6 meters.
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