An arrow is shot straight up in the air at an initial speed of 15.0 m/s. After how much time is the arrow moving downward at a speed of 8.00 m/s? 2 points3.22 s0.714 s2.35 s1.87 s1.24 s
Question
An arrow is shot straight up in the air at an initial speed of 15.0 m/s. After how much time is the arrow moving downward at a speed of 8.00 m/s? 2 points3.22 s0.714 s2.35 s1.87 s1.24 s
Solution
To solve this problem, we need to use the equation of motion that relates final velocity, initial velocity, acceleration and time. The equation is:
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the final velocity (v) is -8.00 m/s (negative because the arrow is moving downward), the initial velocity (u) is 15.0 m/s, and the acceleration (a) is -9.8 m/s² (negative because gravity is pulling the arrow downward).
We can plug these values into the equation and solve for time (t):
-8.00 m/s = 15.0 m/s + (-9.8 m/s²) * t
Rearranging the equation to solve for t gives:
t = (-8.00 m/s - 15.0 m/s) / -9.8 m/s²
t = 23.0 m/s / 9.8 m/s²
t = 2.35 s
So, the arrow is moving downward at a speed of 8.00 m/s after 2.35 seconds. The correct answer is 2.35 s.
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