A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s, and its initial position was 0 m, what is its final position?385 m32 m-242.2 m -385 m242.2 m
Question
A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s, and its initial position was 0 m, what is its final position?385 m32 m-242.2 m -385 m242.2 m
Solution
To find the final position of the car, we can use the equation of motion:
s = ut + 0.5at^2
where: s = final position u = initial velocity t = time a = acceleration
Given: u = 5.1 m/s t = 14 sec a = 3.2 m/s^2
Substituting these values into the equation, we get:
s = (5.1 m/s * 14 sec) + 0.5 * (3.2 m/s^2 * (14 sec)^2)
Calculating the above expression, we get:
s = 71.4 m + 0.5 * 3.2 m/s^2 * 196 sec^2 s = 71.4 m + 0.5 * 627.2 m s = 71.4 m + 313.6 m
So, the final position of the car is s = 385 m.
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