A car has an initial speed of 16 m s-1. It decelerates at 4.0 m s-2 until it stops.What is the distance travelled by the car?A. 4 mB. 16 mC. 32 mD. 64 m
Question
A car has an initial speed of 16 m s-1. It decelerates at 4.0 m s-2 until it stops.What is the distance travelled by the car?A. 4 mB. 16 mC. 32 mD. 64 m
Solution
To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where:
v = final velocity = 0 (since the car stops) u = initial velocity = 16 m/s a = acceleration = -4.0 m/s^2 (negative because it's deceleration) s = distance travelled (which we're trying to find)
Rearranging the equation to solve for s gives us: s = (v^2 - u^2) / 2a
Substituting the given values into the equation gives us: s = (0 - (16)^2) / 2*(-4) = 64 m
So, the correct answer is D. 64 m.
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