A race car starting from rest accelerates uniformly at a rate of 4.90 meters per second2. What is the car's speed after it has traveled 200.00 meters?A 31.3 m/sB 62.6 m/sC 196 m/sD 44.3 m/s
Question
A race car starting from rest accelerates uniformly at a rate of 4.90 meters per second2. What is the car's speed after it has traveled 200.00 meters?A 31.3 m/sB 62.6 m/sC 196 m/sD 44.3 m/s
Solution
To solve this problem, we can use the equation of motion that relates final speed (v), initial speed (u), acceleration (a), and distance (s). The equation is:
v² = u² + 2as
Given in the problem, the car starts from rest, so the initial speed (u) is 0. The acceleration (a) is 4.90 m/s², and the distance (s) is 200.00 m.
Substituting these values into the equation, we get:
v² = 0 + 2 * 4.90 m/s² * 200.00 m v² = 1960 m²/s²
To find v, we take the square root of both sides:
v = sqrt(1960 m²/s²) v = 44.3 m/s
So, the car's speed after it has traveled 200.00 meters is 44.3 m/s. The answer is D.
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