A car traveling 70 km/hr breaks to a speed of zero in in 3.6 seconds. If the acceleration (deceleration) is constant, how far does the car travel in this time?Question 3Select one:a.35 mb.70 mc.19 md.not enough information
Question
A car traveling 70 km/hr breaks to a speed of zero in in 3.6 seconds. If the acceleration (deceleration) is constant, how far does the car travel in this time?Question 3Select one:a.35 mb.70 mc.19 md.not enough information
Solution
To solve this problem, we can use the equation of motion:
d = ut + 0.5at^2
where:
- d is the distance travelled,
- u is the initial speed,
- t is the time, and
- a is the acceleration.
First, we need to convert the initial speed from km/hr to m/s because the time is given in seconds.
70 km/hr = 70 * 1000 m/3600 s ≈ 19.44 m/s
The final speed is 0, so the acceleration (which is actually deceleration in this case) can be found using the equation:
a = (v - u) / t
where:
- v is the final speed,
- u is the initial speed, and
- t is the time.
a = (0 - 19.44) / 3.6 ≈ -5.4 m/s^2
Now we can find the distance:
d = ut + 0.5at^2 d = 19.44 * 3.6 + 0.5 * -5.4 * (3.6)^2 d = 70 + -35.28 ≈ 34.72 m
So, the closest answer is a. 35 m.
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