An object moving with a speed of 3 m/s accelerates uniformly at 17 m/s2 in the direction of its motion for a distance of 7 meters. What is the final speed of the object? Report your answer to one decimal place if the answer is a whole number do not put a decimal in it. Do not type in the unit or the computer will mark your answer incorrect.
Question
An object moving with a speed of 3 m/s accelerates uniformly at 17 m/s2 in the direction of its motion for a distance of 7 meters. What is the final speed of the object? Report your answer to one decimal place if the answer is a whole number do not put a decimal in it. Do not type in the unit or the computer will mark your answer incorrect.
Solution
To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where:
v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance.
Given in the problem: u = 3 m/s, a = 17 m/s^2, and s = 7 m.
Substituting these values into the equation, we get:
v^2 = (3 m/s)^2 + 2*(17 m/s^2)*(7 m) v^2 = 9 m^2/s^2 + 238 m^2/s^2 v^2 = 247 m^2/s^2
Taking the square root of both sides to solve for v, we get:
v = sqrt(247 m^2/s^2) v = 15.7 m/s
So, the final speed of the object is 16 (rounded to the nearest whole number as per the problem's instructions).
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