To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where:

v = final velocity = 19 m/s
u = initial velocity = 5 m/s
a = acceleration (which we are trying to find)
s = distance = 3 m

Rearranging the equation to solve for acceleration gives us: a = (v^2 - u^2) / (2s)

Substituting the given values into the equation gives us: a = ((19 m/s)^2 - (5 m/s)^2) / (2 * 3 m)

Solving this gives us: a = (361 - 25) / 6 = 336 / 6 = 56 m/s^2

So, the magnitude of the car's average acceleration is 56.

Question

To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where:

v = final velocity = 19 m/s
u = initial velocity = 5 m/s
a = acceleration (which we are trying to find)
s = distance = 3 m

Rearranging the equation to solve for acceleration gives us: a = (v^2 - u^2) / (2s)

Substituting the given values into the equation gives us: a = ((19 m/s)^2 - (5 m/s)^2) / (2 * 3 m)

Solving this gives us: a = (361 - 25) / 6 = 336 / 6 = 56 m/s^2

So, the magnitude of the car's average acceleration is 56.

Knowee AI · Accepted Answer

To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where:

v = final velocity = 19 m/s
u = initial velocity = 5 m/s
a = acceleration (which we are trying to find)
s = distance = 3 m

Rearranging the equation to solve for acceleration gives us: a = (v^2 - u^2) / (2s)

Substituting the given values into the equation gives us: a = ((19 m/s)^2 - (5 m/s)^2) / (2 * 3 m)

Solving this gives us: a = (361 - 25) / 6 = 336 / 6 = 56 m/s^2

So, the magnitude of the car's average acceleration is 56.

Question