Analyze the following code:public class Test {   public static void main(String[] args) {     boolean[][] x = new boolean[3][];     x[0] = new boolean[1]; x[1] = new boolean[2];      x[2] = new boolean[3];     System.out.println("x[2][2] is " + x[2][2]);   } } Group of answer choicesThe program has a compile error because new boolean[3][] is wrong.The program has a runtime error because x[2][2] is null.The program runs and displays x[2][2] is null.The program runs and displays x[2][2] is true.The program runs and displays x[2][2] is false.

Analyze the following code. Please select all that apply.  public class Test {   public static void main(String[] args) {     Object a1 = new A();     Object a2 = new Object();     System.out.println(a1);     System.out.println(a2);   } } class A {   int x;   @Override   public String toString() {     return "A's x is " + x;   } } Group of answer choicesThe program cannot be compiled, because System.out.println(a1) is wrong and it should be replaced by System.out.println(a1.toString());When executing System.out.println(a1), the toString() method in the Object class is invoked.When executing System.out.println(a2), the toString() method in the Object class is invoked.When executing System.out.println(a1), the toString() method in the A class is invoked.

Analyze the following code:public class Test {   public static void main(String[] args) {     int[] x = new int[5];     int i;    for (i = 0; i < x.length; i++)      x[i] = i;    System.out.println(x[i]);  }}Group of answer choicesThe program displays 4.The program displays 0 1 2 3 4.The program has a compile error because i is not defined in the last statement in the main method.The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.

Analyze the following code:public class Test {   public static void main(String[] args) {     int[] x = {1, 2, 3, 4};     int[] y = x;    x = new int[2];    for (int i = 0; i < y.length; i++)      System.out.print(y[i] + " ");  }}Group of answer choicesThe program displays 0 0 3 4The program displays 0 0The program displays 0 0 0 0The program displays 1 2

Analyze the following code carefully.public class Test {  int x;  public Test(String t) {     System.out.println("Test");  }  public static void main(String[] args) {    Test test = new Test();    System.out.println(test.x);  }}Group of answer choicesThe program has a compile error because you cannot create an object from the class that defines the object.The program has a compile error because Test does not have a default constructor.The program has a compile error because System.out.println method cannot be invoked from the constructor.The program has a compile error because x has not been initialized.

Analyze the following code.public class Test {   public static void main(String[] args) {     int[] x = new int[3];     System.out.println("x[0] is " + x[0]);   } } Group of answer choicesThe program has a compile error because the size of the array wasn't specified when declaring the array.The program has a runtime error because the array elements are not initialized.The program runs fine and displays x[0] is 0.The program has a runtime error because the array element x[0] is not defined