It takes 100 J to raise the temperature of 14.4 g of ortho-carborane by 6.5 oC. What is the molar heat capacity of ortho-carborane if its molecular formula is C2B10H12 (MW = 144.44)? Give your answer in J/K.mol to 1 d.p Useful Formula...!q = c m ΔTc = q/m*ΔT
Question
It takes 100 J to raise the temperature of 14.4 g of ortho-carborane by 6.5 oC. What is the molar heat capacity of ortho-carborane if its molecular formula is C2B10H12 (MW = 144.44)? Give your answer in J/K.mol to 1 d.p Useful Formula...!q = c m ΔTc = q/m*ΔT
Solution
Sure, let's solve this step by step:
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First, we need to calculate the number of moles of ortho-carborane. We can do this using the formula:
Number of moles = mass / molar mass
So, the number of moles of ortho-carborane = 14.4 g / 144.44 g/mol = 0.1 mol
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Next, we use the formula for specific heat capacity (c) which is:
c = q / (m * ΔT)
But in this case, we are asked for the molar heat capacity, so we need to adjust the formula to:
c = q / (n * ΔT)
where n is the number of moles.
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Substituting the given values into the formula, we get:
c = 100 J / (0.1 mol * 6.5 K) = 153.8 J/K.mol
So, the molar heat capacity of ortho-carborane is 153.8 J/K.mol to 1 decimal place.
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