What is the temperature change if 1400 J of heat is added to 2.94 g of solid beryllium to 1 d.p?(The molar heat capacity of solid beryllium is 16.4 J mol-1 K-1) Useful Formula...!q = c m ΔT
Question
What is the temperature change if 1400 J of heat is added to 2.94 g of solid beryllium to 1 d.p?(The molar heat capacity of solid beryllium is 16.4 J mol-1 K-1) Useful Formula...!q = c m ΔT
Solution
Sure, let's solve this step by step:
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First, we need to convert the mass of beryllium to moles. The molar mass of beryllium is about 9.012 g/mol. So, 2.94 g of beryllium is 2.94 g / 9.012 g/mol = 0.326 mol.
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Next, we can use the formula q = c m ΔT, where q is the heat added, c is the molar heat capacity, m is the number of moles, and ΔT is the change in temperature. We are solving for ΔT, so we rearrange the formula to get ΔT = q / (c m).
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Substituting the given values into the formula, we get ΔT = 1400 J / (16.4 J mol-1 K-1 * 0.326 mol) = 262.4 K.
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So, the temperature change is 262.4 K to 1 decimal place, or 262.4 K.
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