The answer is B. Increase progressively.

Here's why:

1. In sp3 hybridization, the carbon atom is bonded to four other atoms, forming a tetrahedral shape. The bond angle in this case is 109.5 degrees.

2. In sp2 hybridization, the carbon atom is bonded to three other atoms, forming a trigonal planar shape. The bond angle in this case is 120 degrees.

3. In sp hybridization, the carbon atom is bonded to two other atoms, forming a linear shape. The bond angle in this case is 180 degrees.

So, as the hybridization state changes from sp3 to sp2 to sp, the bond angle increases progressively.

Question

The answer is B. Increase progressively.

Here's why:

1. In sp3 hybridization, the carbon atom is bonded to four other atoms, forming a tetrahedral shape. The bond angle in this case is 109.5 degrees.

2. In sp2 hybridization, the carbon atom is bonded to three other atoms, forming a trigonal planar shape. The bond angle in this case is 120 degrees.

3. In sp hybridization, the carbon atom is bonded to two other atoms, forming a linear shape. The bond angle in this case is 180 degrees.

So, as the hybridization state changes from sp3 to sp2 to sp, the bond angle increases progressively.

Knowee AI · Accepted Answer

The answer is B. Increase progressively.

Here's why:

1. In sp3 hybridization, the carbon atom is bonded to four other atoms, forming a tetrahedral shape. The bond angle in this case is 109.5 degrees.

2. In sp2 hybridization, the carbon atom is bonded to three other atoms, forming a trigonal planar shape. The bond angle in this case is 120 degrees.

3. In sp hybridization, the carbon atom is bonded to two other atoms, forming a linear shape. The bond angle in this case is 180 degrees.

So, as the hybridization state changes from sp3 to sp2 to sp, the bond angle increases progressively.

When the hybridisation state of carbon atom changes from sp3 to sp2 and sp, the angle between the hybridized orbitals.A Remains same B Increase progressively C Decrease gradually D All of these