The hybridization of the carbon atom in the cation CH3+ is

The hybridization of the carbon atom in the cation CH3+ is sp2.

Here's the step-by-step explanation:

1. First, we need to determine the number of sigma bonds and lone pairs around the carbon atom. In CH3+, the carbon atom is bonded to three hydrogen atoms and has no lone pairs, so it forms three sigma bonds.

2. The formula to determine the hybridization state is: Hybridization = 1/2 [Number of valence electrons on atom + Number of sigma bonds + Number of lone pairs - Charge on cation]. For carbon, the number of valence electrons is 4.

3. Substituting the values into the formula, we get: Hybridization = 1/2 [4 + 3 + 0 - 1] = 1/2 [6] = 3.

4. The number 3 corresponds to sp2 hybridization (where s is 1 and p is 2, adding up to 3).

So, the hybridization of the carbon atom in CH3+ is sp2.