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What will be the output of the following code?int i;for (i = 0; i < 5; i++) {    if (i == 3) {        break;    }    printf("%d ", i);}

Question

What will be the output of the following code?int i;for (i = 0; i < 5; i++) {    if (i == 3) {        break;    }    printf("%d ", i);}

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Solution

The output of the code will be:

0 1 2

Here's the step by step explanation:

  1. The variable i is initialized with a value of 0.
  2. The for loop starts and checks if i is less than 5. Since i is 0, it is less than 5, so the loop continues.
  3. Inside the loop, there's an if statement that checks if i is equal to 3. Since i is 0, it is not equal to 3,

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1/3

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