What is the output of the code given below?#include <stdio.h> void main() { int i; for (i = 5; i < 10; i++); printf("%d ", i);}Options5105 6 7 8 99

The output of the given code will be 10.

Here's the step by step explanation:

1. The variable 'i' is declared and initialized with the value 5.
2. The 'for' loop will run as long as 'i' is less than 10. With each iteration, 'i' is incremented by 1.
3. However, there is a semicolon (;) immediately after the 'for' loop. This means that the loop has an empty body, so the 'printf' statement is not part of the loop.
4. The 'for' loop will keep incrementing 'i' until 'i' is no longer less than 10. At this point, 'i' will be 10.
5. After the 'for' loop has finished executing, the 'printf' statement will print the current value of 'i', which is 10.