Consider the following code. What is the output?#include <stdio.h>int main() {    int x = 5, y = 0;    for (int i = 0; i < 5; i++) {        y += x;        if (y > 10) break;    }    printf("%d\n", y);    return 0;}

The output of the code will be 15.

Here's the step-by-step explanation:

1. The code initializes two integer variables, x and y, with values 5 and 0 respectively.
2. Then it enters a for loop that will iterate 5 times (from i = 0 to i = 4).
3. In each iteration, the value of x (which is 5) is added to y.
4. After the first iteration, y becomes 5. After the second iteration, y becomes 10.
5. In the third iteration, y becomes 15. At this point, the condition y > 10 becomes true, so the break statement is executed, and the loop is terminated prematurely.
6. Finally, the value of y (which is 15) is printed.