The quadratic equation 4a 2 +13a+3=0 has solutions:

The solutions to the quadratic equation 4a^2 + 13a + 3 = 0 can be found using the quadratic formula, which is given by:

a = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a, b, and c are coefficients of the quadratic equation, which are 4, 13, and 3 respectively.

Step 1: Identify a, b, and c in the given equation. a = 4, b = 13, c = 3

Step 2: Substitute these values into the quadratic formula.

a = [-13 ± sqrt((13)^2 - 443)] / (2*4) a = [-13 ± sqrt(169 - 48)] / 8 a = [-13 ± sqrt(121)] / 8 a = [-13 ± 11] / 8

Step 3: Solve the equation for the two possible values of a.

a = (-13 + 11) / 8 = -2 / 8 = -0.25 a = (-13 - 11) / 8 = -24 / 8 = -3

So, the solutions to the equation 4a^2 + 13a + 3 = 0 are a = -0.25 and a = -3.