Solve the following quadratic equation. 3x 2 +13x+14=0

Sure, here are the steps to solve the quadratic equation 3x^2 + 13x + 14 = 0:

Step 1: Identify the coefficients a, b, and c in the quadratic equation ax^2 + bx + c = 0. In this case, a = 3, b = 13, and c = 14.

Step 2: Use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a), to solve for x.

Step 3: Substitute the values of a, b, and c into the formula.

x = [-13 ± sqrt((13)^2 - 4314)] / (2*3) x = [-13 ± sqrt(169 - 168)] / 6 x = [-13 ± sqrt(1)] / 6

Step 4: Solve for x.

x = [-13 + 1] / 6 and x = [-13 - 1] / 6 x = -12 / 6 and x = -14 / 6 x = -2 and x = -7/3

So, the solutions to the equation 3x^2 + 13x + 14 = 0 are x = -2 and x = -7/3.