3a 2 −14a+12=0

Sure, the equation you provided is a quadratic equation. Here's how to solve it step by step:

1. First, let's rewrite the equation in standard form: 3a^2 - 14a + 12 = 0

2. The standard form of a quadratic equation is ax^2 + bx + c = 0. In this case, a = 3, b = -14, and c = 12.

3. To solve the equation, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

4. Substituting the values of a, b, and c into the formula, we get:

   a = [-(-14) ± sqrt((-14)^2 - 4312)] / (2*3) a = [14 ± sqrt(196 - 144)] / 6 a = [14 ± sqrt(52)] / 6

5. Now, calculate the square root of 52, which is approximately 7.21. Then, substitute this value into the equation:

   a = [14 ± 7.21] / 6 a1 = (14 + 7.21) / 6 ≈ 3.53 a2 = (14 - 7.21) / 6 ≈ 1.13

So, the solutions to the equation 3a^2 - 14a + 12 = 0 are a ≈ 3.53 and a ≈ 1.13.