A car takes 100 metres to decelerate from 25 m s−1 to a complete stop.Which of the following describes all of the known variables in this situation?A$s=100\ \mathrm{m},\ \ u=25\ \mathrm{m\ s^{-1}}$s=100 m,  u=25 m s−1​B$s=100\ \mathrm{m},\ \ u=25\ \mathrm{m\ s^{-1}},\ \ v=0\ \mathrm{m\ s^{-1}}$s=100 m,  u=25 m s−1,  v=0 m s−1​C$s=100\ \mathrm{m},\ \ v=25\ \mathrm{m\ s^{-1}}$s=100 m,  v=25 m s−1​D$s=100\ \mathrm{m},\ \ v=25\ \mathrm{m\ s^{-1}},\ \ u=0\ \mathrm{m\ s^{-1}}$s=100 m,  v=25 m s−1,  u=0 m s−1​

A car takes 100 metres to decelerate from 25 m s−1 to a complete stop.Which of the following constant acceleration equations is best suited to find the time it takes for the car to come to a stop?A$v^2=u^2+2as$v2=u2+2as​B$s=vt-\frac{1}{2}at^2$s=vt−12​at2​C$s=\frac{1}{2}\left(u+v\right)t$s=12​(u+v)t​D

A car is travelling at 96 km/h and subjected to a deceleration of 4.9 m/s2 when the brakes are applied and the car finally comes to a stop. Determine the following:(a) the time it takes for the car to stop, t = Answer seconds,(b) the distance (in metres) the car travels in this time, s = Answer metres.

A car accelerates from 5 m/s to 25 m/s in 100 m.What is the car's average acceleration?

A car is traveling at 25 meters per second when the driver sees a cat crossing the road 100 meters away.  If the car comes to a complete stop in 5 seconds what is the car's acceleration (deceleration)

A car has an initial speed of 16 m s-1. It decelerates at 4.0 m s-2 until it stops.What is the distance travelled by the car?A. 4 mB. 16 mC. 32 mD. 64 m