A car takes 100 metres to decelerate from 25 m s−1 to a complete stop.Which of the following constant acceleration equations is best suited to find the time it takes for the car to come to a stop?A$v^2=u^2+2as$v2=u2+2asB$s=vt-\frac{1}{2}at^2$s=vt−12at2C$s=\frac{1}{2}\left(u+v\right)t$s=12(u+v)tD
Question
A car takes 100 metres to decelerate from 25 m s−1 to a complete stop.Which of the following constant acceleration equations is best suited to find the time it takes for the car to come to a stop?Av2=u2+2asBs=vt−12at2Cs=12(u+v)tD
Solution
The best equation to use in this scenario is A: .
This equation is derived from the equations of motion and is best suited for problems where initial velocity (u), final velocity (v), acceleration (a), and distance (s) are involved.
In this case, we know the initial velocity (u = 25 m/s), the final velocity (v = 0 m/s, since the car comes to a stop), and the distance (s = 100 m). We want to find the time it takes for the car to come to a stop, but first we need to find the acceleration (a).
Once we find the acceleration using equation A, we can then use it in equation B or C to find the time (t).
So, the best suited equation to start with is A: .
Similar Questions
A car is travelling at 96 km/h and subjected to a deceleration of 4.9 m/s2 when the brakes are applied and the car finally comes to a stop. Determine the following:(a) the time it takes for the car to stop, t = Answer seconds,(b) the distance (in metres) the car travels in this time, s = Answer metres.
A car takes 100 metres to decelerate from 25 m s−1 to a complete stop.Which of the following describes all of the known variables in this situation?A$s=100\ \mathrm{m},\ \ u=25\ \mathrm{m\ s^{-1}}$s=100 m, u=25 m s−1B$s=100\ \mathrm{m},\ \ u=25\ \mathrm{m\ s^{-1}},\ \ v=0\ \mathrm{m\ s^{-1}}$s=100 m, u=25 m s−1, v=0 m s−1C$s=100\ \mathrm{m},\ \ v=25\ \mathrm{m\ s^{-1}}$s=100 m, v=25 m s−1D$s=100\ \mathrm{m},\ \ v=25\ \mathrm{m\ s^{-1}},\ \ u=0\ \mathrm{m\ s^{-1}}$s=100 m, v=25 m s−1, u=0 m s−1
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