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What will be the output of the following code?1234567891011121314151617#include <stdio.h>int main() { int a = 100; int *p = &a; int count = 0; while (count < 1) { *p += 1; ++count; } int b = *p; printf("%d, %d", a, b); return 0; }

Question

What will be the output of the following code?1234567891011121314151617#include <stdio.h>int main() { int a = 100; int *p = &a; int count = 0; while (count < 1) { *p += 1; ++count; } int b = *p; printf("%d, %d", a, b); return 0; }

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Solution

The output of the code will be "101, 101".

Here's the step-by-step explanation:

  1. The integer variable a is declared and initialized with the value 100.
  2. A pointer p is declared and it is initialized with the address of a. So, p is pointing to a.
  3. An integer variable count is declared and initialized with 0.
  4. A while loop is started which will run until count is less than 1.
  5. Inside the loop, the value at the address pointed by p (which is a) is incremented by 1. So, a becomes 101.
  6. count is incremented by 1. Now count is 1 and the loop will not run again.
  7. An integer variable b is declared and it is initialized with the value at the address pointed by p (which is a). So, b becomes 101.
  8. The values of a and b are printed which are both 101. So, the output is "101, 101".

This problem has been solved

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