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What will be the output of the following code snippet?123456789101112131415#include <stdio.h> int main() { char direction = 'N'; if (direction == 'N') printf("North"); else if (direction == 'S') printf("South"); else if (direction == 'E') printf("East"); else if (direction == 'W') printf("West"); else printf("Unknown"); return 0; }

Question

What will be the output of the following code snippet?123456789101112131415#include <stdio.h> int main() { char direction = 'N'; if (direction == 'N') printf("North"); else if (direction == 'S') printf("South"); else if (direction == 'E') printf("East"); else if (direction == 'W') printf("West"); else printf("Unknown"); return 0; }

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Solution

The output of the code will be "North".

Here's the step by step explanation:

  1. The code starts with the inclusion of the standard input/output library of C, #include <stdio.h>.

  2. The main() function is declared, which is the entry point of the program.

  3. Inside the main() function, a character variable direction is declared and initialized with the value 'N'.

  4. Then, an if-else if-else control structure is used to check the value of direction.

  5. The first if condition checks if direction is equal to 'N'. If it is, "North" is printed to the console.

  6. If direction is not 'N', the program checks the next else if condition to see if direction is 'S'. If it is, "South" is printed.

  7. This process continues for 'E' and 'W', printing "East" and "West" respectively.

  8. If direction is none of 'N', 'S', 'E', or 'W', "Unknown" is printed.

  9. In this case, since direction is 'N', the output of the program will be "North".

  10. The program then returns 0, indicating successful execution of the program.

This problem has been solved

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